Question

$\huge \dag \: \underline{ \bf Question :-}$



A force is applied to a mass of 16 kg for 3 seconds. As the force is removed the mass moves 81 meters in 3 seconds. What was the value of the force applied?



- Don't spam :))​

Answer 1

Answer:

The value of the force applied is 144 N.

v = 81 m /3 s = 27 m/s. Since mass moves in 3 s is 81 m when the force removed. Therefore, the mass moves with uniform velocity (no acceleration) for next 3 s. F = 144 N.

Answer 2

Given:-

• Mass = 16 kg
• Distance = 81 m
• Time = 3 sec

$\sf \: \green{Velocity \: = \frac{ \cancel{ 81m}}{ \cancel{3sec} } }\\ \\ \\ \sf \: \green{ = 27m/s}$

The acceleration of mass on first 3 sec when force is present,

$\sf \color{green}{\: a = \frac{v - u}{t} } \\ \\ \sf \: \color{green}= \frac{27 - 0}{3} \\ \\ \color{green}9m/ {s}^{2}$

Now we will use Newtons law of motion,

$\tt \boxed{ \tt \green{ f= ma} }\\ \\ \sf \: \color{lime}f = 16 \times 9 \\ \\ \sf \: \color{lime} f = 144N$

Thus, the value of force applied (in first three sec) is 144 N.

Hope it helps uh!...❤