Question

$\huge \displaystyle\sf\lim\limits_{x\to\infty}\sqrt[x]{\dfrac{x!}{x^{x}}}$Or$\displaystyle\sf\lim\limits_{x\to\infty}\left(\dfrac{x!}{x}\right)^{\left(\dfrac{1}{x}\right)}$​

Answer 1

Answer:

$\huge \sf{\underbrace{\underline{Elucidation:-:}}}$

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Answer 2

Answer:

Oyee merai bin akal Ben buddhi walai bro ...xD

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