Question

$\huge \fbox \blue{Question}$ :-

Solve for X and also verify it :-

$\tt \: 2(x + \frac{1}{x}) {}^{2} = 10 - x - \frac{1}{x}$

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Answer 1

Step-by-step explanation:

$\sum_{i=1}^{n}i=\frac{1}{2}n\cdot(n+ 1)$\\[10pt] ... 1 foo \fbox{$ f(x)=\int_1^{\infty}\frac{1}{x^2}\,\ mathrm{d} x=1 $} bar ... 10 \newcommand{\org@theeq}{} ... \textrm{d}) & y & = & ax^{3}+bx^{2}+cx+d & (cubic).

Answer 2

Answer:

2(x+ 1/x)²=10-x- 1/x

2(x²+1/x²)=10-x-1/x

2x²+2/x²=10x-x²-1/x

2x⁴+2/x²=10x-x²-1/x

x(2x⁴+2)=x²(10x-x²-1)

2x⁴+2x=10x³-x⁴-x²

2x⁴+2x-10x³-x⁴+x²=0

x⁴-10x³+x²+2x=0

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