Question

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ln a trapezium, the parallel sides measure 40 cm and 20 cm. Calculate the area of the trapezium if its non-parallel sides are equal having the lengths of 26 cm
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Answer 1

The parallel sides of an isosceles trapezium = 40 cm and 20 cm.

The equal sides = 26 cm.

The distance between the parallel sides

$= [26^2-{ \frac{(40 - 20)}{2} }^2]^{0.5}</p><p>$

$= [676–10^2]^{0.5 }\\ = (676–100)^{0.5 }\\ = 576^{0.5} \\ = 24 cm.$

Area of trapezium = (40+20)×24/2 = 720 sq cm.