A motor car increases its velocity from 40 kmph to 60 kmph in 5 seconds. What will be the perimeter of acceleration of this motor car?
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Given:
Initial velocity (u)=20 km/h
=5.55m/s
Final velocity (v)=30 km/ h
=8.33 m/s
Time=10seconds
FORMULA TO BE USED
a=v-u/t
=8.33-5.55/10
=0.278 m/s^2
therefore, its acceleration is 0.278m/s^2
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