Question

$\huge\fbox\orange{Question \:↓}$
Find the solution..
$= \geqslant \frac{2x}{3} - \frac{x - 1}{6} + \frac{7x - 1}{4} = 2 \frac{1}{6}$
​

Answer 1

$\bold{Given :} \\ \\ = = > \frac{2x}{3} - \frac{x - 1}{6} + \frac{7x - 1}{4} =2 \frac{1}{6} \\ \\ \bold{Solution :} \\ \\ = = > \frac{2x}{3} - \frac{x - 1}{6} + \frac{7x - 1}{4} =2 \frac{1}{6} \\ \\ Now , \: L.C.M \: of \: 3 , 6 \: and \: 4 = 12 . \: \\ Therefore : \\ \\ = = > \frac{8x - 2x - 2 + 21x - 3}{12} = \frac{13}{6} \\ \\ = = > \frac{27x - 5}{12} = \frac{13}{6} \\ \\ = = > 6(27x - 5) = 13 \times 12 \\ \\ = = > 162x - 30 = 156 \\ \\ = = > 162x = 156 + 30 \\ \\ = = > 162x = 186 \\ \\ = = > x = \cancel{\frac{186}{162} } \\ \\ = = > \bold \pink{x = \frac{31}{27} }$

Answer 2

Answer:

x = 1

Step-by-step explanation:

$(\frac{2x}{3}- \frac{x-1}{6})+\frac{7x-1}{4}=2\frac{1}{6} \\\\\frac{4x-x+1}{6} + \frac{7x-1}{4}=\frac{13}{6} \\\\\frac{3x+1}{6}+\frac{7x-1}{4}=\frac{13}{6} \\\\\frac{6x+2+21x-3}{12}=\frac{13}{6} \\\\ \frac{27x-1}{12}=\frac{13}{6} \\\\27x-1=\frac{13*12}{6} \\27x-1=26\\27x=27\\x=1\\Ans.$