Question

$\huge\fbox\pink{@Siddhi163}$. → A ball at rest is dropped from a height of 12 m.If it looses 25% of its kinetic energy on striking the ground and bounces back to height 'h'is equal to?​

Answer 1

$\huge\fbox\pink{@BrainlyAryan7}$

The kinetic energy on reaching the ground will be equal to the initial potential energy, i.e. KE=mg(12).

Since the remaining kinetic energy (after loss) will be used to rise the block to height h,

mg(12)(1−0.25)=mgh

Hence, h=9 m

Answer 2

Answer:

The kinetic energy on reaching the ground will be equal to the initial potential energy, i.e. KE=mg(12).Since the remaining kinetic energy (after loss) will be used to rise the block to height h,mg(12)(1−0.25)=mghHence, h=9 m.

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