Question

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A bus starting from rest masses with a uniform acceleration of 2 m/s for 4 minutes. a)find the speed acquired. b)find the distance travelled​

Answer 1

Answer:

Given :

Initial velocity, u = 0 m/s (as it is starting from rest)

Acceleration, a = 2 m/s²

Time, t = 4 minutes

To find :

Speed acquired, v

Distance travelled, s

According to the question,

Note :

1 minute = 60 seconds

4 minutes = 4 × 60 = 240 seconds

By using Newtons first equation of motion,

➞ v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

➞ Substituting the values,

➞ v = 0 + 2 × 240

➞ v = 0 + 480

➞ v = 480

So,the speed acquired is 480 m/s.

Now,

By using Newtons third equation of motion,

➞ s = ut + ½ at²

Where,

s = Distance

u = Initial velocity

a = Acceleration

t = Time

➞ Substituting the values,

➞ s = 0 × 240 + ½ × 2 × 240 × 240

➞ s = 0 + 57600

➞ s = 57600

So,the distance travelled is 57600 meters.

Answer 2

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Answer:

Given :

Initial velocity, u = 0 m/s (as it is starting from rest)

Acceleration, a = 2 m/s2

• Time, t = 4 minutes

To find :

• Speed acquired, v

• Distance travelled, s

According to the question,

Note :

• 1 minute = 60 seconds

4 minutes = 4 x 60 = 240 seconds =

By using Newtons first equation of motion,

u +at - v =Where,

• v = Final velocity

u

=

Initial velocity

• a = Acceleration

t = Time

Substituting the values,

→ v = 0 + 2 × 240

- v = 0 + 480

- v = 48O

So,the speed acquired is 480 m/s.

Now,

By using Newtons third equation of motion,

→ s = ut + 12 at?

Where,

s = Distance

• u = Initial velocity

• a = Acceleration

t = Time

Substituting the values,→ s = 0 x 240 + 12 x 2 × 240 x 240

→ s = 0 + 57600

S = 57600

So, the distance travelled is 57600 meters.