Question

[tex]\huge\fbox\pink{QUESTION BY SIDDHI♡}[/tex}. If a line passes through the pôint P(1,-2) and cuts the circle x²+y²-x-y=0 at A and B,then the maximum value of PA+PB is?​

Answer 1

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GIVEN:-

line passes through the pôint P(1,-2) and cuts the circle x²+y²-x-y=0 at A and B.

TO FIND:-

PA + PB

SOLUTION:-

Circle x²+y²-x-y=0

Centre:- [½,½], radius = 1/√2

Maximum value of PA + PB is When AB is Diameter of Circle.

Hence, PA + PB = √26

• I Hope it's Helpful My Friend.

Answer 2

Step-by-step explanation:

GIVEN:

line passes through the pôint P(1,-2) and cuts the circle x²+y²-x-y=0 at A and B.

TOFIND:-

PA + PB

SOLUTION:-

Circle x²+y²-x-y=0

Centre:- [½,½], radius = 1/√2

Maximum value of PA + PB is When AB is Diameter of Circle.

Hence, PA + PB = √26