Question

$\huge\fbox\red{h}\fbox\green{e}\fbox\blue{l}\fbox\orange{l}\fbox\purple{o}$
☆Draw a circle of radius 4 cm. Draw any two of its non-parallel chord. Construct the perpendicular bisectors of these chords. Where do they meet?
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Answer 1

(1)

Mark any point C on the sheet. Now, by adjusting the compasses up to 4cm and by putting the pointer of compasses at point C, turn the compasses slowly to draw the circle. It is the required circle of 4cm radius.

(2)

Take any two chords AB and CD in the circle.

(3)

Taking A and B as centres and with radius more than half of AB, draw arcs on both sides of AB, intersecting each other at E, F. Join EF which is the perpendicular bisector of AB.

(4)

Taking C and D as centres and with radius more than half of CD, draw arcs on both sides of CD, intersecting each other at G, H. Join GH which is the perpendicular bisector of CD.

Now, we will find that when EF and GH are extended, they meet at the centre of the circle i.e., point O

hope it helps you

reffer to the attachment