Question

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An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?



➳ REQUIRED GOOD ANSWER​

Answer 1

$\huge{\mathfrak\red{Answer}}$

Required answer to find the maximum number of column which they can march:-

{H.C.F of 616,32}

${\mathfrak\red{Which \: is \: larger}}$

616>32

${\pink{By \: applying \: the \: law \: of \: Euclid's \: division \: algorithm \: to \: 616 \: and \: 32 \: to \: get}}$

616= 32×19+8

Divide it till you get the zero as a remainder

Let us assume the divisor 32 and remainder 8, and apply the division lemma to get

32= 8×4+0

.°. We cannot get the remainder 0, can't find the answer!

Hence the divisor at the last process= 8

.°. The H.C.F of 616, 32 is 8.

Therefore, 8 is the maximum number of columns they can march.

Khadijah21

Answer 2

Step-by-step explanation:

the HCF of 32 and 616 is 8

Hence, the required number of maximum columns is 8