Question

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In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (with a stirrer) of mass 0.16 kg at 15°C. After stirring, the final temperature is found to be 45°C. If the specific heat of water is 4,200 J/kg/°C,

(a) what is the quantity of heat released per kg of water per 1°C fall in temperature?

(b) Calculate the heat energy released by water in the experiment in cooling from 70°C to 45°C. (c) Assuming that the heat released by water is entirely used to raise the temperature of calorimeter from 15°C to 45°C) calculate the specific heat capacity of copper. ​

Answer 1

A,By definition, amount of heat released per kg per 1oC fall in temperature is specific heat capacity of water =4200Jkg−1oC−1.

B,Mass of water = 0.2 kg.

C,Heat energy absorbed by calorimeter = mSt

=0.16×S×(45−15)=4.8S

Now, Heat given = Heat taken

4.8S=2100⇒S=4.82100=437.5Jkg−1oC−1

Answer 2

Answer:

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