Question

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A hemisphere of maximum possible diameter is placed over a cuboidal block of side 7 cm. Find the surface area of the solid so formed.​

Answer 1

Answer:

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$A \: hemisphere \: of \: maximum \: possible \: diameter \\ is \: placed \: over \: a \: cuboidal \: block \: of \\ side \: 7 \: cm. \: \\ Find \: the \: surface \: area \: of \: the \: solid \\ so \: formed. \bigstar$

ANSWER

ANSWERThe greatest diameter=side of the cube=7cm.

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of Hemisphere

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side 2

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side 2

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side 2 =6×7×7

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side 2 =6×7×7=294sq cm

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side 2 =6×7×7=294sq cmSurface Area of Base of Hemisphere is,

ANSWERThe greatest diameter=side of the cube=7cm.The radius of the hemisphere =3.5cm.Now,The Surface Area of Solid=Surface Area of Cube - Surface Area of Base Hemisphere + Curve Surface Area of HemisphereSurface Area of Cube=6×side 2 =6×7×7=294sq cmSurface Area of Base of Hemisphere is,= πr

πr 2

πr 2

πr 2 = 7×3.5

22

=38.5cm

=38.5cm 2

=38.5cm 2Curved Surface Area of Hemisphere is,

=38.5cm 2Curved Surface Area of Hemisphere is,=2×38.5

=38.5cm 2Curved Surface Area of Hemisphere is,=2×38.5=77sq cm

=38.5cm 2Curved Surface Area of Hemisphere is,=2×38.5=77sq cm∴ total Surface Area is =294−38.5+77

=38.5cm 2Curved Surface Area of Hemisphere is,=2×38.5=77sq cm∴ total Surface Area is =294−38.5+77=332.5sq cm.

Answer 2

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ㅤㅤ‎ㅤㅤㅤㅤㅤA hemisphere of maximum possible diameter is placed over a cuboidal block of side 7 cm. Find the surface area of the solid so formed.

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Surface area of of soild = Surface area of cubiod have side 7 cm +Surface area of a hemisphere having maximum diameter

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$= 6 \times ( {side)}^{2} + 3\pi \: {r}^{2}$

Where R is surface area of sphere

$= 6 \times {7}^{2} + 3 \times 22 \div 7 \times ( {7 \div 2) }^{2} \\ = 6 \times 49 + 3 \times 22 \div 7 \times 49 \div 4 \\ = 294 + 115.50 \\ = 409.50 {cm}^{2}$

if you will take diameter of hemisphere along the diagonal of a cubiod it will just come out of surface i. e it will the cross the Boundary of cubiod.

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