Determine:
(i) sin A, cos A
(ii) sin C, cos C
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In Δ ABC, right-angled at B ,using Pythagoras theorem we have
AC² = AB² +BC² = 576 + 49 = 625
Or AC=25 ( taking positive value only)
Now
(i) In a right angle triangle ABC where B=90° ,
Sin A = BC/AC = 7/25
CosA = AB/AC = 24/25
(ii) Sin C = AB/AC = 24/25
Cos C = BC/AC =7/25
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