Question

$\huge \fbox \red{❥ Question}$

Find two numbers whose sum is 27 and product is 182.​

Answer 1

Let the numbers be x , y .

according to question the equations are ,

xy = 182 ..... ( 1 )

x + y = 27 ...... ( 2 )

From eq 2 , we get

x = 27 - y ......... ( 3 )

now substitute eq 3 in eq 1 , we get

$(27 - y)(y) = 182$

$- {y}^{2} + 27y - 182 = 0$

Answer 2

Answer:

I have solved it so easily.

Step-by-step explanation:

Let the first number be x then the second number will be 27−x.

x(27-x)=182

⇒27x − x(2) =182

⇒x(2) − 27x + 182=0

⇒x(2) − 13x − 14x+ 182=0

⇒x(x−13) − 14 (x−13)=0

⇒(x−14)(x−13)=0

⇒x=14,13

If the first number is 14, then the second number is 13 and if the first number is 13, then the second number is 14.

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