How to find tan(-pi)?
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Answer:
Apply the definition:
tan(x)=sin(x)cos(x)
So,
tan(−π)=sin(−π)cos(−π)
Actually, you may notice that −π and π identify the same angle, since you're making half of a turn, either clockwise or counterclockwise, but still ending at (−1,0). So, we may simplify the expression into
tan(−π)=tan(π)=sin(π)cos(π)
Now, π is a known value for trigonometric function, and I've actually already wrote the answer: since the angle π is associated to the point (−1,0), and for every point P=(x,y) identified by the angle α on the unit circumference you have (cos(α),sin(α))=(x,y), we have
(cos(π),sin( π ))=(−1,0)
and thus
tan( -π) = tan (π)= sin(π)÷cos (π) =0/-1 = 0
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