If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠ A = ∠ B.
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According to the question:-
Let cosA= Side adjacent A/Hypotenuse AC/AB
Similarly,cosB= Side adjacent B/Hypotenuse=BC/AB
Given thatcosA=cosBAC/AB = BC/AB AC=BC
In triangle,angles opposite equal side are equal ∠B=∠A
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