Question

$\huge \fbox \red{❥ Question}$


Solve 2x + 3y = 11 and 2x – 4y = – 24 and hence find the value of ‘m’ for which y = mx + 3.






(REQUIRED QUALITY ANSWER)​

Answer 1

Answer

Given equations are

2x+3y=11−−−−(1)

2x−4y=−24−−−−(2)

Form (1)

2x+3y=11

⇒2x=11−3y

⇒x= 11−3y/2 −−−(3)

substituting x in(2)

2x−4y=−24

⇒2( 11−3y/2 )−4y=−24

⇒11−3y−4y=−24

⇒11−7y=−24

⇒7y=35

⇒y=35/7

⇒y=5.

putting y = 5 in (3)

x= 11−3(5)/2

⇒x= 11−15/2

⇒x=−4/2

∴x=−2.

Hence x = -2 and y = 5 is the solution of the

equation.

Now, we have to find m

y=mx+3 ∴m=−1

5=3(−2)+3

5−3=−2m⇒−2m=2

⇒m=−2/x=−1