the area of trapezium of height 10 cm is 240 cm². If the length of one of its side its parallel sides is 25 cm, find the length of the other parallel side .
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Answer:
Area of trapezium = 1/2 x (sum of
parallel sides ) x Height
Area is given = 240
A/Q, 1/2x (24+36) x H = 240
1/2x 60 x H = 240
30 xH= 240
H 240/30 8
The distance between them = 8 cm
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Let AB (=24m ) be guy wire attached to a vertical pole BC of height 18 m. To keep the wire taut let it fixed to stake at A Then ABC is a right triangle right angled at C
AB² =AC² +BC²
so ∴24² =AC² +18²
or AC² =576−324
or AC² =252
or AC= √252
AC=6√7m
therefore the stake may be placed at a distance of 6√7 m from the base of pole
Step-by-step explanation:
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