The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.
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Question:–
The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.
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Answer:–
Let the cost of bat be x and ball be y.
Now,
CASE 1 [7 bat, 6 balls]:-
==>7x+6y=3800
==>7x+6y=3800Let this () be eq.(i)
CASE 2 [3bat, 5 balls]:-
==>3x+5y=1750
Let this () be eq.(ii)
Multiplying eq.(i) with 3 we get:-
==>21x+18y=11400
Let this () be eq.(iii)
Multiplying eq.(ii) with 7 we get:-
==>21x+35y=12250
Let this () be eq.(iv)
Subtracting eq.(iii) from eq.(iv) we get:-
==>21x+35y–(21x+18y)=12250–11400
==>21x–21x+35y–18y=850
==>17y=850
==>y=850÷17
==> y = 50
Substituting the value of y in eq.(i) we get:–
==>7x+6[tex] \times [/tex]50=3800
==>7x+300=3800
==>7x=3800–300
==>7x=3500
==>x=3500÷7
==> x=500
⭐Hence the cost of bat is ₹500 and the cost of ball is ₹50
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