Question

$\huge \fbox \red{❥ Question}$


Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.​

Answer 1

$\huge\purple{\mid{\fbox{\tt Hi\:Mate}\mid}}$

$\Large\color{red}Question$

Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.

$\Large\bold\blue{Answer : 8cm}$

$\Large\color{red}Solution$

Let O be the centre of the concentric circle of radii 5 cm and 3 cm respectively. Let AB be a chord of the larger circle touching the smaller circle at P.

Then

$\small\bold\orange{ AP =\: PB \: and\: OP⊥AB}$

Applying Pythagoras theorem in △OPA, we have

$\small\fbox\pink{OA² \:= \:OP²\: +\:AP²}$

⇒ 25 = 9 + AP²

⇒ 25 - 9 = AP²

⇒AP² = 16

⇒ AP = $\sqrt{16}$

⇒ AP = 4 cm

⇒ AB = 2AP

⇒AB = 2 × 4

$\Large\fbox\blue{∴ 8cm}$

$\Large\color{aqua}Happy\:Learning$

$\Large\fbox\red{Mark\:As\:Brainliest}$

Answer 2

Answer:

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