Math, asked by Zerina313121, 4 months ago

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500 men took dip in a tank which is 80 m long , 50 m broad. What is the rise in Water level if the average displacement of water displaced by man is 4 m³?​

Answers

Answered by Anonymous
0

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Volume of water displaced by 500 men =

(4x \times 500) = 22 \:  {m}^{3}

Area of tank =

 = 80 \times 50 = 4000 \:  {m}^{2}

let the rise in the level of water = h metres

then , \: 4000 \times h  = 2000

⇒h =  \frac{2000}{4000}  = 0.5 \: m

Hence the rise in water level is 0.5 m

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Answered by ItzNiladoll
2

Step-by-step explanation:

GIVEN:-

LENGTH = 80m

BREADTH = 50m

TO FIND:-

THE RISE IN WATER LEVEL

SOLUTION:-

VOLUME OF WATER DISPLACED BY 500 MEN =(4×500)=2000m^3

AREA OF THE TANK = 80×50=4000m^2

LET THE RISE IN THE LEVEL OF WATER

= h metres.

Then 4000 × h= 2000

HENCE THE RISE OF WATER LEVEL IS 2000

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