Question

$\huge\fbox{\underline{\red{Q} \blue{U} \green{E} \orange{S} \purple{T} \pink{I} \green{O} \red{N}}}$


If 1/3 of a number exceeds its 2/7 by 1, find the number. ​

Answer 1

let the number =x

1/3 of a number = x/3

2/7 of the number = 2x/7

Given:

1/3 of a number exceeds its 2/7 by 1

(1/3)x = (2/7)x + 1

(1/3 - 2/7)x = 1

(7 - 6)x/21 = 1

x/21 = 1

x = 21

Required number = x =21

Answer 2

Answer:

$\bigstar\mathtt {\large{ \underline{solution}}}$

✿ Here the concept of Linear pair in one variable is used.

✿According to the question 1/3 of a number exceeds its 2/7 by 1.

$\mathtt{ \implies\color{red} \: Let \: us \: assume \: the \: unknown \: number \: be \: x}$

so

$\mathtt{\implies\frac{1}{3} \: of \: number = \frac{x}{3} }\\ \\ \mathtt{\implies\frac{2}{7} \: of \: number = \frac{2x}{7}}$

${ \underline {\sf{ \to \: Now \: the \: equation \: formed \: will \: be }}}$

$\sf{ \implies \: \frac{1x}{3} = \frac{2x}{7} +1 }\\ \\ \sf{ \implies \: \frac{1x}{3} - \frac{2x}{7} =1 }\\ \\ \sf{ \underline{ Take\: L.C.M}}\\ \\ \sf{ \implies\frac{7x - 6x}{21} = 1 } \\ \\ \sf{ \implies 7x - 6x = 21} \\ \\ \sf{ \implies x = 21}$

$\color{orange} \mathtt{⚡So \: the \: required \: number \: is \: 21 }$

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