Question

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The sum of digits of a two-digit number is 7 if the digits are reversed the new number is equal to 3 less than 4 times the original number find the original number. ​

Answer 1

Question ⤵️

The sum of digits of a two-digit number is 7 if the digits are reversed the new number is equal to 3 less than 4 times the original number find the original number.

Answer ⤵️

1 + 6 = 7

1 + 6 = 761 = 4(16) - 3

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 3

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)x

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.x = 1

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.x = 1Therefore, y = 6

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.x = 1Therefore, y = 61 + 6 = 7

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.x = 1Therefore, y = 61 + 6 = 710(6) + 1 = 4(10(1) +6) - 3

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.x = 1Therefore, y = 61 + 6 = 710(6) + 1 = 4(10(1) +6) - 361 = 40 + 24 - 3

1 + 6 = 761 = 4(16) - 3Let’s set original number at (10x +y) and the reversed digit number as (10y + x).It has already been defined that x + y = 7.The reversed digit number will be (4 * (original number)) - 310y + x = 4(10x + y) -3Solve for y.y = -1/2 + (13/2)xPlug into x + y = 7, and solve for x.x = 1Therefore, y = 61 + 6 = 710(6) + 1 = 4(10(1) +6) - 361 = 40 + 24 - 361 = 61

Answer 2

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