Question

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Find the value:
» (-10m²n⁶)×(-20mn¹⁵) m= 1.2 and n=-1​

Answer 1

Answer:

(-10m²n⁶)×(-20mn¹⁵)=200m³n²¹=200×(1.2)³×(-1)²¹

=200×1.728×-1=-345.6

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Answer 2

Step-by-step explanation:

Given :-

(-10m^2n^6)×(-20mn^15)

To find:-

Find the value of (-10m^2n^6)×(-20mn^15)

at m = 1.2 and n= -1 ?

Solution:-

Method-1:-

Given Product is (-10m^2n^6)×(-20mn^15)

=>(10×20)×(m^2×m)×(n^6×n^15)

We know that a^m × a^n = a^(m+n)

=>200×m^(2+1) ×n^(6+15)

=>200×m^3×n^21

(-10m^2n^6)×(-20mn^15) = 200×m^3×n^21

Given that

m= 1.2

n= -1

Now , On Substituting the values of m and n in

the above product then,

=>200×(1.2)^3×(-1)^21

=>200×1.2×1.2×1.2×-1

=>200×1.728×-1

=> -345.6

Method -2:-

Given Product is (-10m^2n^6)×(-20mn^15)

If m = 1.2 and n = 1 then

=>[(-10×(1.2)^2×(-1)^6]×[-20×1.2×(-1)^15]

=>[-10×1.2×1.2×1]×[-20×1.2×-1]

=>(-10×1.44)×(20×1.2)

=>(-14.4)×(24)

=> -345.6

Answer:-

The value of (-10m^2n^6)×(-20mn^15)

at m = 1.2 and n= -1 is -345.6

Used formula:-

• a^m × a^n = a^(m+n)
• If n is odd number in (-1)^n then the value of(-1)^n is -1 and if n is even then the value of (-1)^n is 1