Question

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•Which term of the A.P. 6, 13, 20, 27 . . . . is 98 more than its 24th term?
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Answer 1

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Given Ap

is 6,13,20,27,

first term = a = 6

Common difference =d= t2-t1-13-6-7

nth term =tn=a+(n-1)d

Let pth term=t24+98

a+(p-1)7=a+(24-1)7+98

(p-1)7-23×7+98

(p-1)7=7(23+14)

p-1-37

p = 38

Required term = 38

Answer 2

Answer:

is 6,13,20,27,

first term = a = 6

Common difference =d= t2-t1-13-6-7

nth term =tn=a+(n-1)d

Let pth term=t24+98

a+(p-1)7=a+(24-1)7+98

(p-1)7-23×7+98

(p-1)7=7(23+14)

p-1-37

p = 38

Required term = 38

Step-by-step explanation:

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