Question

$\huge\fcolorbox{blue}{aqua}{Hola \:Mate!}$
Draw the graphs of the following equations and find the

vertices of the triangle formed between the lines and the

x-axis. Find the area of the triangle so formed. Also, find

the area of the triangle formed between the lines and the

y-axis. Now, find the ratio of the area of the triangle formed

between the lines and the x- axis and the triangle formed

between the lines and the y-axis.

2x + y - 6 = 0 and 4x – 2y - 4 = 0.

SPAMMERS WILL BE REPORTED TO MODERATORS.​

Answer 1

Answer:

Haye Mate!!

Step-by-step explanation:

2x+y-6=0___eq.1

4x-2y-4=0____eq.2

Substract eq.1 from eq. 2

4x-2y-4=0

-2x-y+6=0

Multiplying 2 in eq.2 and 4 in eq1 to balance

8x-4y-8=0

-8x-4y+24=0

-8y+16=0

-8y= - 16

8y=16

Y=2

Put the value of y in any one eq

Taking eq 1

2x+y-6=0

2x+2-6=0

2x-4=0

2x=4

X=2

Value of x and y = 2