Math, asked by ⲘⲅJαcк, 1 month ago


\huge\fcolorbox{blue}{pink}{QUESTION}


Tʜᴇ sɪᴅᴇs ᴏғ ᴀ ʀɪɢʜᴛ ᴀɴɢʟᴇᴅ ᴛʀɪᴀɴɢʟᴇ ᴀʀᴇ (8x-1) ᴄᴍ (3x+2) ᴄᴍ ᴀɴᴅ (4x+9) ᴄᴍ ɪғ ᴛʜᴇ ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ᴛʜᴇ ᴛʀɪᴀɴɢʟᴇ ɪs 40ᴄᴍ. Fɪɴᴅ ᴛʜᴇ ʟᴇɴɢᴛʜ ᴏғ ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ.


⚔ Sᴘᴀᴍᴍɪɴɢ = I'ᴅ REPORT ​​

Answers

Answered by ITSSAURAV
4

answer

Aur answer </p><p></p><p></p><p>perimerter=sumofallsides⇒40=(8x−1)+(3x+2)+(4x+9)⇒40=8x−1+3x+2+4x+9⇒40=15x+10⇒40−10=15x⇒30=15x⇒x=1530⇒x=2 \\ sidesofthetriangleare :−</p><p>\begin{gathered}⇒ \: (8x - 1) = 8(2) - 1 = 15 \\ \\ ⇒ \: (3x + 2) = 3(2) + 2 = 8 \\ \\ ⇒ \: (4x + 9) =4 (2) + 9 = 17\end{gathered}⇒(8x−1)=8(2)−1=15⇒(3x+2)=3(2)+2=8⇒(4x+9)=4(2)+9=17

Answered by ⲘⲓssRσѕє
5

Answer:

\huge\fcolorbox{blue}{pink}{☃αղsաҽɾ☃}

perimerter=sumofallsides

⇒40=(8x−1)+(3x+2)+(4x+9)

⇒40=8x−1+3x+2+4x+9

⇒40=15x+10

⇒40−10=15x⇒30=15x

⇒x=30/15

⇒x=2

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