Math, asked by ItzMrVinay, 2 months ago


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FIND  \:  \: X,IF \: ( \frac{3}{2}) {}^{ - 3}  \times ( \frac{3}{2}) {}^{5}  =  (\frac{3}{2} ){}^{2x + 1}
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Answers

Answered by jitendrabansal
1

Answer:

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Answered by 3636rohitbankoti25
1

( \frac{3}{2} )^{ - 3}  \times  (\frac{3}{2}) ^{5} =  (\frac{3}{2})  ^{2x + 1}  \\  (\frac{2}{3} )^{3}  \times  (\frac{3}{2} ) {}^{5}  =  (\frac{3}{2})  {}^{2x + 1}  \\  \frac{8}{27}  \times  \frac{243}{32}  =  (\frac{3}{2} ) {}^{2x + 1}  \\  \frac{9}{4}  = ( \frac{3}{2} ) {}^{2x + 1}  \\  (\frac{3}{2} ) {}^{2}  =  (\frac{3}{2} ) {}^{2x + 1}  \\   exponents \:  \:  2x + 1 = 2 \\  2x = 2 - 1 \\ x = 1 \div 2 \\ x =  \frac{1}{2}

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