Joldi solve kro dikra (≧∇≦)
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Answer:
1−cotx=1−cosxsinx=sinx−cosxsinx
and, similarly,
1−tanx=cosx−sinxcosx
the left-hand side can be written
sin2xsinx−cosx+cos2xcosx−sinx
Using the common denominator sinx−cosx , we get
sin2x−cos2xsinx−cosx
and the conclusion is at one step.
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