Question

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The total surface area of a hollow metal cylinder, open at both ends, of external radius 8 cm and height 10 cm is 338 π cm2. Taking 'r' to be the inner radius. Write down an equation in r and use it to find the thickness of the metal in the cylinder.


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Answer 1

Answer:

Given:-

• External radius of cylinder is 8 cm.
• Height of cylinder is 10 cm.
• Total surface area of cylinder is 338pi cm^2.

▪Let external radius be R.

Find the thickness of Metal in the cylinder.

formula used:-

• Total surface area of cylinder

=2pi h (R-r)(R^2-r^2)

Solution ↓ ↓ ↓ ↓

Total surface area of cylinder=338pi cm^2.

2pi h (R-r)+(tR^2-r^2) =338pi cm^2.

2h (R-r)+(R^2-r^2)=338 cm^2.

2*10 (8-r)+(64-r^2)=338 cm^2.

20 (-r^2-r+72)=338

-r^2-r+72=338/20.

r^2+r-72=-16.9

Now solve this quadratic equation.

Answer 2

Answer:

Hlo dear

Step-by-step explanation:

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