Math, asked by itsme0163, 10 months ago


\huge\green{\tt{\underline{\underline{ solve it :-}}}}

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Answers

Answered by Anonymous
4

\color{plum} {\tt {\bigstar}} \ \displaystyle {\tt{Thank uuh}}

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Answered by stoysem
5

 \blue{\bold{\underline{\underline{Step- by - step - explanation:-}}}}

 \frac{x + 1}{2}  -  \frac{2}{x + 1}  =  \frac{x + 1}{3}  +  \frac{3}{x + 1}  -  \frac{5}{6}

 \frac{3( x  + 1 ) - 2(x + 1)  + 5}{6}  =  \frac{3 - 2}{x + 1}

 \frac{3x + 3 - 2x - 2 + 5}{6}  =  \frac{1}{x + 1}

 \frac{x + 6}{6}  =  \frac{1}{x + 1}

or,

(x + 6)(x + 1)  = 6.1

or,

 {x}^{2}  + 7x + 6 - 6 = 0

or,

 {x}^{2}  + 7x = 0

or,

x(x + 7) = 0

Either,

x = 0

or,

(x + 7) = 0

or,

x =  - 7

∴ The required answer is 0 and -7.

 \blue{\bold{\underline{\underline{Be Brainly. }}}}

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