Question

$\huge \maltese\bold \color{brown} \: Question$
Caliculate the mass and volume of oxygen required at STP to convert 2.4kg of graphite into carbon dioxide.

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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The chemical equation for the process is:

C+O

2

→CO²l

For the above reaction, 1 mole of O

2

will burn 1 mole of C completely.

In 2.4 g C, number of moles =

12

2.4

=0.2 moles of oxygen is required.

Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.

Therefore, 0.2 mol O2

=0.2×22.4 L

=4.48L.

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