Question

$\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Question}$
if the lenght of the daigonals of a rectangle is 26 cm and the lenght of its base is 24 find the lenght of the altitude of rectangle



✰with explanation
✰no copy paste ​

Answer 1

Step-by-step explanation:

Let ABCD be the rectangle.

l(BC) = 24cm, l(AC) = 26cm

In ∆ABC, m∠ABC = 90° …[Angle of a rectangle]

∴[l(AC)]2 = [l(AB)]2 + [l(BC)]2 …[Pythagoras theorem]

∴ (26)2 = [l(AB)]2 + (24)2

∴ (26)2 – (24)2 = [l(AB)]2

∴(26 + 24) (26 – 24) = [l(AB)]2 …[∵ a2 – b2 = (a + b)(a – b)]

∴ 50 x 2 = [l(AB)]2

∴100 = [l(AB)]2

i.e. [l(AB)]2 = 100

∴ l(AB) = √100 …[Taking square root of both sides] ∴ l(AB) =10 cm

∴The length of the other side is 10 cm.

I have not done any copy paste.