Question

$\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Question}$
three ropes of lenghts 48 cm,96 cm , 104 cm are to be cut into equal pieces find the greatest possible lenght of the piece and total lenght


don't spam
​

Answer 1

$\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Question}$

Three ropes of lenghts 48 cm,96 cm , 104 cm are to be cut into equal pieces find the greatest possible lenght of the piece and total lenght.

$\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Answer}$

The solution is very simple.

You just have to find find the H.C.F (Highest Common Factor) of length of ropes and that will be the answer

• H.C.F of 48m, 96m, and 104m gives us the required length.

Try it yourself!!

$\:$

Answer 2

Step-by-step explanation:

16=2×2×2×2

20=2×2×5

Maximum length of the piece that has to be cut=H.C.F of 16m and 20m

Now HCF of 16 and 20 is 4

∴ Required length=4m

mark as brainliest pls