Question

$\huge\mathbb{\pink{QUESTION ♡- }}\star{}$




A stone is hanged on a string and moving it in Vertical Plane.
Calculate the value of Tension at uppermost point and lowermost point.

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Answer 1

$\huge✎\fbox \orange{QUE} ST \fbox\green{ION}☟$

A stone is hanged on a string and moving it in Vertical Plane. Calculate the value of Tension at uppermost point and lowermost point.

$\huge✍︎\fbox\orange{ÂŇ}\fbox{SW} \fbox\green{ÊŘ}:$

${When \: the \: stone \: is \: at \: the \: bottom} \\ {position \: forces \: acting \: on \: stone \: are:} \\ \\ </p><p></p><p>{Upward \: force \: tension (T),}  \\ {Downward \: forces \: are \: weight (mg) }\\ {and \: also \:   \frac{ {mv}^{2} }{R} \:  centrifugal \: force.} \\ </p><p> \\ </p><p>{So \: balancing \: forces \: we \: get :} \\ </p><p> \\ </p><p>T=mg+\frac{{mv}^{2}}{R}$

$And \: minimum \: tension \: is \: obtained\\ at \: highest \: point \: which \: will \: be: \\ </p><p> \\ \green{T=mg−  \frac{ {mv}^{2} }{R} }$

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Answer 2

\huge✎\fbox \orange{QUE} ST \fbox\green{ION}☟✎

QUE

ST

ION

☟

A stone is hanged on a string and moving it in Vertical Plane. Calculate the value of Tension at uppermost point and lowermost point.

\huge✍︎\fbox\orange{ÂŇ}\fbox{SW} \fbox\green{ÊŘ}:✍︎

A

ˆ

N

ˇ

SW

E

ˆ

R

ˇ

:

\begin{gathered}{When \: the \: stone \: is \: at \: the \: bottom} \\ {position \: forces \: acting \: on \: stone \: are:} \\ \\ < /p > < p > < /p > < p > {Upward \: force \: tension (T),} \\ {Downward \: forces \: are \: weight (mg) }\\ {and \: also \: \frac{ {mv}^{2} }{R} \: centrifugal \: force.} \\ < /p > < p > \\ < /p > < p > {So \: balancing \: forces \: we \: get :} \\ < /p > < p > \\ < /p > < p > T=mg+\frac{{mv}^{2}}{R}\end{gathered}

Whenthestoneisatthebottom

positionforcesactingonstoneare:

</p><p></p><p>Upwardforcetension(T),

Downwardforcesareweight(mg)

andalso

R

mv

2

centrifugalforce.

</p><p>

</p><p>Sobalancingforcesweget:

</p><p>

</p><p>T=mg+

R

mv

2

\begin{gathered}And \: minimum \: tension \: is \: obtained\\ at \: highest \: point \: which \: will \: be: \\ < /p > < p > \\ \green{T=mg− \frac{ {mv}^{2} }{R} }\end{gathered}

Andminimumtensionisobtained

athighestpointwhichwillbe:

</p><p>

T=mg−

R

mv

2

\footnotesize\bold\red{\overbrace{\underbrace \mathbb\blue{Please \: Mark \: As \: The \: Brainliest\: If\: It\: Satisfied\:You}}}

PleaseMarkAsTheBrainliestIfItSatisfiedYou

꧁Hopes so that this will help you,꧂

♥️With Love♥️

✌︎Thanking you, your one of the Brother of your 130 Crore Indian Brothers and Sisters.✌︎

\large\red{\underbrace{\overbrace\mathbb{\colorbox{aqua}{\colorbox{blue}{\colorbox{purple}{\colorbox{pink}{\colorbox{green}{\colorbox{gold}{\colorbox{silver}{\textit{\purple{\underline{\red{《❀PŘÎ᭄ŇCĒ✿》࿐}}}}}}}}}}}}}}

《❀P

R

ˇ

I

ˆ

᭄

N

ˇ

C

E

ˉ

✿》࿐

Tumhe Kse PTA m Marathi Hu!?