Question

$\huge\mathbb{\pink{QUESTION ♡- }}\star{}$

Referred to the image...​

Answer 1

SOLUTION-;

Given,

P1 = 76 cm Hg,

P2 = 7.6 cm of Hg,

V1 = 30 m3, V2 = ?

T1 = 27 + 273 = 300 K

T2 = -54 + 273 = 219 K

By gas equation,

$\frac{p1 \: v1}{t1} = \frac{p2v2}{t2}$

$v2 = \frac{p1v1t2}{t1p2} = \frac{76 \times 3 0\times \times 219}{300 \times 7.6} = 219 {m}^{3}$

So increase in volume of gas = 219 – 30 = 189 m3.

Answer 2

Answer:

SOLUTION-:

Given,

P1 = 76 cm Hg,

P2 = 7.6 cm of Hg,

V1 = 30 m3, V2 = ?

T1 = 27 + 273 = 300 K

T2 = -54 + 273 = 219 K

More further reffered to the attachment

Explanation:

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Warm regards:Kanika