Question

$\huge\mathbb\purple{\boxed{\boxed{QuEStiON :-}}}$

A body moves with a uniform velocity of 4m/s starting it's journey t=0. Another body starting from rest moves with acceleration 1m/s from the same point at t=0. When and where the two bodies will meet ?

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Answer 1

Answer:

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Explanation:

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Answer 2

$\large\bf\underline {To \: find:-}$

• When the two bodies will meet.

$\large\bf\underline{Given:-}$

• initial velocity of 1st body is 4m/s
• acceleration of 2nd body is 1m/s²

$\huge\bf\underline{Solution:-}$

Velocity of 1st body = 4m/s

Acceleration of 2nd body = 1m/s²

Distance covered by 1st body:-

As we know that,

✯ V = s/t

➻ 4 = S/t

➻ 4t = S1

➻ S1= 4t .....1)

♦︎ Distance covered by 2nd body :-

As we know that,

✯S = ut + ½at²

➳S2 = 0 + ½× 1 × t²

➳S2 = t²/2 ....2)

♦︎ When they meet

From (1) and (2)

♦︎ S1 = S2

➳4t = t²/2

➳ 8 = t

• v = s/t

➻ s = v × t

➻ s = 4 × 8

➻ s = 32m

Hence

The two bodies will meet at 32m .

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