Question

$\huge\mathbb\red{Question}$

The terms in two positions of some Arithmetic Sequence are given below . Write the first 5 terms.

1) 3rd term = 2
5th term = 3

3) 4th term = 2
7th term = 3​

Answer 1

Answer:

If we consider that these given terms are of an Arithmetic progression series then it is very easy to calculate.

Let ‘a' be the first term and ‘d’ be the common difference of the arithmetic series

Here, 4th term = 2

i.e. a + 3d = 4 (————————————#)

7th term = 3

i.e. a + 6d = 2 (—————————————@)

Now we have two variables, i.e. “a” and “d” and two equations also.

Solving equations # and @, we get

a = 1 and,

d= 1/3

1st term = a = 1

2nd term = a+d = 1 + 1/3 = 4/3

3rd term = a+2d = 1+ 2×( 1/3) = 5/3

5th term = a +4d = 1+ 4×(1/3) =7/3

6th term = a+5d = 1+ 5×(1/3) = 8/3.

Hope you get it.

Answer 2

Step-by-step explanation:

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