Question

$\huge\mathbb{\underline{Question}}$

Factorise :- (x^2 -2x ) ^2 -2 (x^2 - 2x ) -3

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Answer 1

Answer:

(x^2 -2x ) ^2 -2 (x^2 - 2x ) -3    (let  (x^2 -2x ) = t

= t^2-2t-3

=t^2-3t+t-3

=t(t-3)+1(t-3)

=(t-3)(t+1)

=(x^2-2x-3)(x^2-2x+1)

=(x^2-3x+x-3)(x^2-2.x.1+1^2)

=(x(x-3)+1(x-3))(x-1)^2

=(x-3)(x+1)(x-1)(x-1)  

Step-by-step explanation:

Answer 2

Answer:

(x^2 -2x ) ^2 -2 (x^2 - 2x ) -3    (let  (x^2 -2x ) = t

= t^2-2t-3

=t^2-3t+t-3

=t(t-3)+1(t-3)

=(t-3)(t+1)

=(x^2-2x-3)(x^2-2x+1)

=(x^2-3x+x-3)(x^2-2.x.1+1^2)

=(x(x-3)+1(x-3))(x-1)^2

=(x-3)(x+1)(x-1)(x-1)