Question

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Find $x$ if ${8}^{3x + 2} \div 8 = {8}^{10}$

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Answer 1

Answer:

${8}^{3x + 2} \div 8 = {8}^{10}$

So we will apply exponent rules that is

$3x + 1 = 10$

So subtract 1 from both sides

$3x + 1 - 1 = 10 - 1 \\ \\ 3x = 9 \\ \\ \therefore \: x = \frac{ { \cancel9} \: \: ^{3} }{ \cancel3} \\ \\ \boxed{ \sf \blue{ x = 3}}$

Hope it helps you from my side :)

Answer 2

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• x = 4

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