Question

$\huge\mathcal\color{teal} Question :-$

The sum of three consecutive multiples of 11 is 363. Find these multiples ?

❥︎ ᵍⁱᵛᵉ ˢᵗᵉᵖ ᵇʸ ˢᵗᵉᵖ ᵉˣᵖˡᵃⁿᵃᵗⁱᵒⁿ

❥︎ ᵏⁱⁿᵈˡʸ ᵍⁱᵛᵉ ᵗʰᵉ ᵃⁿˢʷᵉʳ ʷⁱᵗʰᵒᵘᵗ ˢᵖᵃᵐ​

Answer 1

Answer:

Answer:–

Given:–

• The sum of three consecutive multiples of 11 is 363.

To find:–

• The three multiples=?

Solution:–

Let the three consecutive multiples of 11 are 11x,11(x+1) and 11(x+2).

Sum of three terms=363

$11x + 11x + 11 + 11x + 22 = 363$

$33x + 33 = 363$

$x + 1 = 11$

$x = 10$

So,The three consecutive terms of 11are,

$11x = 11(10) = 110$

$11x + 11 = 110 + 11 = 121$

$11x + 22 = 110 + 22 = 132$

The three terms are 110,121,132

Answer 2

Answer:

GIVEN:-

11(x-1)+11(x)+11(x+1)=363

11(x-1+x+x+1)=363

33x=363

x=11

therefore the consecutive no. s are:-

10,11,12