Question

$\huge\mathcal\colorbox{lavender}{{\color{b}{Question}}}$

Solve the Example.

Doctor Has Prescribed a lens having power + 1.5D . What will be the focal length of the Lence ? What is the type of the lens and what must be the defect of vision​

Answer 1

Explanation:

Question :

• Doctor Has Prescribed a lens having power + 1.5D . What will be the focal length of the Lence ? What is the type of the lens and what must be the defect of vision

given :

• lens having power = 1.5D

to find :

• what must be the defect of vision = ?

• what must be the defect of vision = ?

solution :

• lens of power = +1 .5 D

then ,

• lens of focal length,

• focal = 1/p = +1/1.5 = +0.67

thus ,

• power of the lens is (+ve), the lens is converging.

Answer 2

$\huge\mathcal\colorbox{lavender}{{\color{b}{Question}}}$

Doctor Has Prescribed a lens having power + 1.5D . What will be the focal length of the Lence ? What is the type of the lens and what must be the defect of vision

$\huge\mathcal\colorbox{pink}{{\color{b}{To \ Find}}}$

• The lens..
• The defect of vision..

$\huge\mathcal\colorbox{magenta}{{\color{b}{Solution}}}$

$\textsf{Given:}$

Power of lens, P=+1.5 D

$\textsf{Concept:}$

Eye Defect and its.

$\textsf{Correction:}$

Hypermetropia or farsightedness..

Now, focal length of lens,

f=$\dfrac{1}{P}$ =$\dfrac{1}{1.5}$=0.67 m

Since, the focal length is positive, the lens prescribes for correction is convex lens.. Thus, the defect of fission is farsightedness or hypermetropia..