Question

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From Adjoining Figure,
Angle ABC = 90°
Angle DCB = 90°
AB = 6
DC = 8

Than,

A(∆ABC)/A(∆BCD) = ?
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Diagram in the attachment!

Class:- 10th

Answer with Full Solution!
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Answer 1

Given:-

• ∠ABC = 90°

• ∠DCB = 90°

• AB = 6 cm

• DC = 8 cm

To Find:-

Area of ΔABC ÷ Area of ΔBCD

Formula Used:- Area of triangle = 1/2 × Base × Height

Solution:-

→ Area of ∆ABC = 1/2 × (AB × BC)

→ 1/2 × (6 × BC)

Similarly,    

→ Area of ∆DCB= 1/2 × (8 × BC)

Now,  

→ (Area of ∆ABC) ÷ (Area of ∆DCB) = {1/2 × (6 × BC) ÷ 1/2 × (8 × BC)}  

→ (6 × BC) ÷ (8 × BC) = $\frac{6}{8}$

 

Answer:- $\frac{6}{8}$

Hope it helps you army !