Question

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ɪɴ ᴀ ᴄᴇʀᴛᴀɪɴ ᴄᴏʟʟᴇɢᴇ, 40% ᴏꜰ ᴛʜᴇ ꜱᴇɴɪᴏʀ ᴄʟᴀꜱꜱ ꜱᴛᴜᴅᴇɴᴛꜱ ᴀʀᴇ ᴛᴀᴋɪɴɢ ᴘʜʏꜱɪᴄꜱ, 30% ᴀʀᴇ ᴛᴀᴋɪɴɢ ᴄᴀʟᴄᴜʟᴜꜱ ᴀɴᴅ 10% ᴀʀᴇ ᴛᴀᴋɪɴɢ ʙᴏᴛʜ. ɪꜰ 40 ꜱᴛᴜᴅᴇɴᴛꜱ ᴀʀᴇ ᴇɴʀᴏʟʟᴇᴅ ɪɴ ᴛʜᴇ ꜱᴇɴɪᴏʀ ᴄʟᴀꜱꜱ, ʜᴏᴡ ᴍᴀɴʏ ꜱᴛᴜᴅᴇɴᴛꜱ ᴀʀᴇ ᴛᴀᴋɪɴɢ ɴᴇɪᴛʜᴇʀ ᴘʜʏꜱɪᴄꜱ ɴᴏʀ ᴄᴀʟᴄᴜʟᴜꜱ?


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Answer 1

Answer:

I want to count the 10% that take both courses only once,

so I will include them in the 40% that take Physics,

but not in the 30% that take calculus.

Therefore I have counted 40% + (30% - 10%) = 60%

of the students.

 

60% of 40 students are enrolled in these 2 courses.

.6%2A40+=+24

Therefore 40+ -+24+= +16

16 students are enrolled in neither of these courses

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Hope it helps you!!