Math, asked by hltiwaria, 1 month ago


 \huge\mathcal\colorbox{teal}{question}
A Cristern can be filled by one tap in 4 hours and by another in 5 hours. How long will it take to fill if both tapes are opened together?
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Answers

Answered by Ahanam57
3

According to the question, a cistern takes 4 hours to be filled by first tap to its fullest capacity. Therefore, the correct time taken to fill it with water is 4 hours.

Answered by Animator1100
0

\huge \colorbox{teal}{ Solution}

Let us call the flow rates of the two taps $a$ and $b$ litres per hour. Then we are given that:

\huge</p><p>\begin{array}{ll}</p><p>a&amp;=\text{flow rate of 1st tap}= \frac{\text{Cistern capacity}}{4 \:\text{hours}} \\</p><p>b &amp;=\text{flow rate of 2nd tap}=\frac{\text{Cistern capacity}}{5 \:\text{hours}}</p><p>\end{array}</p><p>

When the taps are running together, the total flow rate into the cistern is $a+b$ litres per hour. Therefore, the time taken to fill the cistern when both taps are open is given by:

\huge</p><p>\frac{\text{Cistern capacity}}{a+b} \: \text{hours}</p><p>

Substituting for a and b:

\huge </p><p>\frac{\text{Cistern capacity}}{\Big(\frac{\text{Cistern capacity}}{4}\Big)+ \Big(\frac{\text{Cistern capacity}}{5}\Big)} = \boxed{\frac{20}{9} \:\text{hours}}</p><p>

So the answer is \huge\boxed{\frac{20}{9} \:\text{hours}}

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