Math, asked by Anonymous, 9 hours ago

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Interegate:-
\  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ \displaystyle \sf \: \int \dfrac{ \sin^{2}x - \cos ^{2} x}{ \sin \: x. \cos \: x}

Answers

Answered by XxitzZBrainlyStarxX
5

Question:-

\sf \large \int \dfrac{ sin^{2}x - cos ^{2} x}{ sin \: x. cos \: x}

Solution:-

 \sf \large \int \frac{sin { }^{2}x  - cos {}^{2} x}{sin \: x.cos \: x} dt =  \sf \large \int \bigg( \frac{sin \: x}{cos \: x}  -  \frac{cos \: x}{sin \: x}  \bigg)dx

 \sf \large =  \int tan \: xdx -  \int cot \: xdx

 \sf \large = log |sec \: x|  - log |sin \: x|  + c.

Answer:-

{ \boxed{ \sf \large \red{\sf \large \int \dfrac{ sin^{2}x - cos ^{2} x}{ sin \: x. cos \: x}  \sf \large = log |sec \: x|  - log |sin \: x|  + c.}}}

Hope you have satisfied.

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