Question

$\huge\mathcal{\fcolorbox{aqua}{azure} {\red{ question}}}$



Calculate the following from the provided circuit diagram. a) Total resultant resistance b) The total current c) Voltage across 3.6
​

$can \: \: anyone \: \: answer \: \: plz$

$full \: \: Explanation \: need$
​

Answer 1

Answer:

20 is the correct answer.

Explanation:

please mark me as brainliest.

Answer 2

hi friend!!!

here you go

Answer:

a) The resultant resistance is 9Ω.

b) Total current in the circuit is 0.5 A.

c) Voltage across 3.6 Ω resistor is 1.8 V.

Explanation:

a) Total resultant resistance :

The resistor R2 is parallel with R4 and R5. R4 and R5 are in series.

⇒ R series = R4 + R5

⇒ R series = 1Ω + 3Ω

⇒ R series = 4Ω

⇒ R4,5 = 4Ω

The resistor R2 is parallel with R4,5

⇒ 1/RP = 1/R2 + 1/R4,5

⇒ 1/RP = 1/6 + 1/4

⇒ 1/RP = (4 + 6)/24

⇒ 1/RP = 10/24

⇒ RP = 2.4 Ω

R1, RP and R3 are in series,

⇒ 3 + 2.4 + 3.6

⇒ 3 + 6

⇒ 9 Ω

Therefore, the resultant resistance is 9Ω.

___________________

b) Total Current in circuit :

⇒ I = V/R

⇒ I = 4.5/9

⇒ I = 0.5 A

Therefore, total current in the circuit is 0.5 A.

___________________

c) Voltage across 3.6 Ω :

The resistor of 3.6 Ω is in series. Which means the current in the circuit is constant.

⇒ V = I × R

⇒ V = 0.5 × 3.6

⇒ V = 1.8 V

Therefore voltage across 3.6 Ω resistor is 1.8 V.

$\huge\color{pink}\boxed{\colorbox{Black}{Thank me }}$

$\huge\color{pink}\boxed{\colorbox{Black}{if you are satisfied}}$