In a triangle , the length of the first side is 5 cm less than the length of the second side . The length of the third side is 7 cm more than the length of the first side if the first side is of length is 18 cm , then what is the semiperimeter of the triangle?
DON'T SPAM ONLY ✓ ANSWERS .
QUALITY ANSWERS
Answers
Answer:
Length of first side is :- 18cm ( given )
Length of second side :- Is 5 times greater than first side :- 18 + 5 = 23 cm
Length of third side :- 7 more than first side :- 18 + 7 = 25cm
First = 18
Second = 23
Third = 25
Semiperemeter =
:
:
:
Therefore, Semiperemeter of given Traingle is 33cm
Given :
The length of the first side is 5 cm less than the length of the second side .
The length of the third side is 7 cm more than the length of the first side .
Length of first side is 18 cm .
To Find :
Semi Perimeter of Triangle .
Solution :
\longmapsto\tt{Let\:second\:side\:be=x}⟼Letsecondsidebe=x
Length of the first side is 5 cm less than the length of the second side . So ,
\longmapsto\tt{First\:side=x-5}⟼Firstside=x−5
Also ,
The length of the third side is 7 cm more than the length of the first side . So ,
\longmapsto\tt{Length\:of\:third\:side=x-5+7}⟼Lengthofthirdside=x−5+7
Length of first side is 18 cm :
\longmapsto\tt{x-5=18}⟼x−5=18
\longmapsto\tt{x=18+5}⟼x=18+5
\longmapsto\tt\bf{x=23}⟼x=23
Therefore :
\longmapsto\tt{Length\:of\:first\:side=18\:cm}⟼Lengthoffirstside=18cm
\longmapsto\tt{Length\:of\:second\:side=x}⟼Lengthofsecondside=x
\longmapsto\tt\bf{23\:cm}⟼23cm
\longmapsto\tt{Length\:of\:third\:side=23-5+7}⟼Lengthofthirdside=23−5+7
\longmapsto\tt\bf{25\:cm}⟼25cm
For Semi Perimeter :
a = 18 cm
b = 23 cm
c = 25 cm
Using Formula :
\longmapsto\tt\boxed{Semi\:Perimeter=\dfrac{a+b+c}{2}}⟼
SemiPerimeter=
2
a+b+c
Putting Values :
\longmapsto\tt{\dfrac{18+23+25}{2}} ⟼
2
18+23+25
\longmapsto\tt{\cancel\dfrac{66}{2}} ⟼
2
66
\longmapsto\tt\bf{33\:cm}⟼33cm
So , The Semi Perimeter of Triangle is 33 cm .