Question

$\huge\mathcal{\fcolorbox{lime}{black}{\green{QUESTION:-}}}$




4. Prove that a line drawn through the mid-point of one side of a triangle parallel to another
side bisects the third side (Using converse of basic proportionality theorem).



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Answer 1

Answer:

ANSWER

Given:

In △ABC,D is midpoint of AB and DE is parallel to BC.

∴ AD=DB

To prove:

AE=EC

Proof:

Since, DE∥BC

∴ By Basic Proportionality Theorem,

DB

AD

=

EC

AE

Since, AD=DB

∴

EC

AE

=1

∴ AE=EC

Explanation:

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Answer 2

Answer:

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Explanation:

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